5c^2-16c+3=0

Solution for 5c^2-16c+3=0 equation:

Simplifying
5c2 + -16c + 3 = 0

Reorder the terms:
3 + -16c + 5c2 = 0

Solving
3 + -16c + 5c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(1 + -5c)(3 + -1c) = 0

Subproblem 1
Set the factor '(1 + -5c)' equal to zero and attempt to solve:

Simplifying
1 + -5c = 0

Solving
1 + -5c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -5c = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -5c = 0 + -1
-5c = 0 + -1

Combine like terms: 0 + -1 = -1
-5c = -1

Divide each side by '-5'.
c = 0.2

Simplifying
c = 0.2
Subproblem 2
Set the factor '(3 + -1c)' equal to zero and attempt to solve:

Simplifying
3 + -1c = 0

Solving
3 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -1c = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -1c = 0 + -3
-1c = 0 + -3

Combine like terms: 0 + -3 = -3
-1c = -3

Divide each side by '-1'.
c = 3

Simplifying
c = 3
Solution
c = {0.2, 3}